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jquery浮点加加减乘除法运算方法实现

JavaScript HTML我帮您 1年前  0次浏览
javascript的除法结果会有误差,在两个浮点数运算时的时候会比较明显。
$.extend({
multi:function(v1,v2){
//乘法
var m = 0, s1 = v1.toString(), s2 = v2.toString();
try { m += s1.split(".")<1>.length } catch (e) { }
try { m += s2.split(".")<1>.length } catch (e) { }
return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m);
},
division:function (arg1,arg2){
//除法
var t1=0,t2=0,r1,r2;
try{t1=arg1.toString().split(".")<1>.length}catch(e){}
try{t2=arg2.toString().split(".")<1>.length}catch(e){}
with(Math){
r1=Number(arg1.toString().replace(".",""))
r2=Number(arg2.toString().replace(".",""))
return (r1/r2)*pow(10,t2-t1);
}
},
sub:function (arg1,arg2){
//减法
var r1,r2,m,n;
try{r1=arg1.toString().split(".")<1>.length}catch(e){r1=0}
try{r2=arg2.toString().split(".")<1>.length}catch(e){r2=0}
m=Math.pow(10,Math.max(r1,r2));
//last modify by deeka
//动态控制精度长度
n=(r1>=r2)?r1:r2;
return ((arg1*m-arg2*m)/m).toFixed(n);
},
add:function(arg1, arg2) {
//加法
var r1, r2, m, c;
try { r1 = arg1.toString().split(".")<1>.length } catch (e) { r1 = 0 }
try { r2 = arg2.toString().split(".")<1>.length } catch (e) { r2 = 0 }
c = Math.abs(r1 - r2);
m = Math.pow(10, Math.max(r1, r2));
if (c > 0) {
var cm = Math.pow(10, c);
if (r1 > r2) {
arg1 = Number(arg1.toString().replace(".", ""));
arg2 = Number(arg2.toString().replace(".", "")) * cm;
}
else {
arg1 = Number(arg1.toString().replace(".", "")) * cm;
arg2 = Number(arg2.toString().replace(".", ""));
}
}
else {
arg1 = Number(arg1.toString().replace(".", ""));
arg2 = Number(arg2.toString().replace(".", ""));
}
return (arg1 + arg2) / m ;
}
});



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